# OpenType MATH Fonts

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We note that $x\mapsto\Im(f(x))$ is the integrand above. We also note that the poles of $f$ are $z^{\pm}=-1\pm 2i$. By choosing the right contour, one can show that $\int_{-\infty}^{+\infty}f(x)dx=-2i\pi\sum_{\stackrel{z\text{residue}}{\Im(z)<0% }}\mathrm{Res}(f,z)$ and thus $\int_{-\infty}^{+\infty}\frac{16\sin(2x+\pi)}{5(x^{2}+2x+5)^{2}}dx=\frac{\pi% \sin(2)}{e^{4}}$